Control of Common Bus
Frequently Asked Questions
Ans: The control gates for the seven flip-flops can be determined in a similar manner. For example, Table 5-6 shows that lEN may change as a result of the two instructions ION and !OF. view more..
Ans: The registers of the computer connected to a common bus system are shown in Fig. 5-4. The control inputs of the registers are LD (load), INR (increment), and CLR (clear). Suppose that we want to derive the gate structure associated with the control inputs of AR. We scan Table 5-6 to find all the statements that change the content of AR view more..
Ans: he block diagram of the control logic gates is shown in Fig. 5-6. The inputs to this circuit come from the two decoders, the I flip-flop, and bits 0 through 11 of IR. The other inputs to the control logic are: AC bits 0 through 15 to check if AC = 0 and to detect the sign bit in AC( view more..
Ans: The 16-bit common bus shown in Fig. 5-4 is controlled by the selection inputs S2, S1, and 50• The decimal number shown with each bus input specifies the equivalent binary number that must be applied to the selection inputs in order to select the corresponding register. Table 5-7 specifies the binary numbers for S2S1S0 that select each register. Each binary number is associated with a Boolean variable x1 through x7, corresponding to the gate structure that must be active in order to select the register or memory for the bus. view more..
- DATA TYPES
- NUMBER SYSTEM
- CONVERSION - INTRODUCTION
- OCTAL AND HEXADECIMAL NUMBER CONVERSION
- OCTAL AND HEXADECIMAL NUMBER CONVERSION -2
- Introduction to Decimal Representation
- ALPHANUMERIC REPRESENTATION
- Complements -2
- Subtraction of Unsigned Numbers
- Subtraction of Unsigned Numbers-2
- Fixed-Point Representation
- Integer Representation
- Arithmetic Addition
- ARITHMETIC SUBTRACTION
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